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Bug #8299 xsl:include doesn't work
Submitted: 2000-12-16 18:58 UTC Modified: 2001-01-16 06:26 UTC
From: jpoon88 at yahoo dot com Assigned:
Status: Closed Package: Sablotron XSL
PHP Version: 4.0.3pl1 OS: RedHat Linux
Private report: No CVE-ID: None
 [2000-12-16 18:58 UTC] jpoon88 at yahoo dot com
We encountered an error when using "xsl:include" syntax.
It always return "error no: 242 " when I transform my xml 
file with my xsl file. I use the same file with MS XML Parser 3.0, it work okay. I confirmed with Tom Kaiser that 
xsl:include is supported in 0.43, but it's definitely better to upgrade to 0.44 (and to 0.5 when it's out finally).


Here is the listing of the files for your testing:
 
XSL file: test.xsl
------------------
 <xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
 
 <xsl:output method="html"/>
 <xsl:include href="test2.xsl"/>
 
 <xsl:template match="/">
 <html><head>This is header</head>
 <body>
 <xsl:apply-templates select="node()"/>
 </body>
 </html>
 </xsl:template>
 
 </xsl:stylesheet>
 

 XSL file: text2.xsl
 -------------------
 <xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
 
 <xsl:template match="bold">
 <P><B><xsl:value-of select="."/></B></P>
 </xsl:template>
 
 <xsl:template match="red">
 <P style="color:red"><xsl:value-of
 
 select="."/></P>
 
 <p> Testing</p>
 </xsl:template>
 
 <xsl:template match="italic">
 <P><i><xsl:value-of select="."/></i></P>
 </xsl:template>
 
 </xsl:stylesheet>
 
 XML File: data.xml
 ------------------
 <?xml version="1.0"?>
 <?xml-stylesheet type="text/xsl" href="test.xsl"?>
 <xslTutorial>
         <bold>Hello, world.</bold>
         <red>I am </red>
         <italic>fine.</italic>
 </xslTutorial>
 
What's meaning of the error code 204? Anyone have similar problem????

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 [2001-01-16 06:26 UTC] sterling@php.net
You must specify the absolute path to the xslt document you are including (feedback from the user).
 
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