php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login

go to bug id or search bugs for

Doc Bug #8106 array_pop problem when using against an array returned from a class
Submitted: 2000-12-04 21:10 UTC Modified: 2001-03-17 00:33 UTC
From: drew at cwa dot co dot nz Assigned:
Status: Closed Package: Documentation problem
PHP Version: 4.0.3pl1 OS: Debian GNU/Linux
Private report: No CVE-ID: None
View Developer Edit
 [2000-12-04 21:10 UTC] drew at cwa dot co dot nz 
Seems to return no TRUE value when using array_pop () on an array returned by a class.

Code Example:

<?
class Form {

      function parse ($arg) {
      
               ereg("(.*)&\[(.?)\]", $arg, $query);
               
               return $query;

      }

}

$form = new Form;

$output = $form->parse($QUERY_STRING);

$number = array_pop($output);

if ($number) { echo "\$number exists"; }

foreach ($output as $tmp) {
        if (($tmp)&&($tmp != $QUERY_STRING)) {
           echo "$tmp<Br>";
        }
}

?>

Patches

Pull Requests

History

AllCommentsChangesGit/SVN commitsRelated reports
 [2000-12-05 06:15 UTC] sniper@php.net 
If you pass a non-array to array_pop() it just displays an
error message. 

After checking the sources for this function, it looks
like it doesn't return anything in case of this error.

Do you mean it should return FALSE in case of this error?
(I think it should)

But if you pass an empty array for array_pop() it
won't return anything but will not display any error 
messages either which I think is the right behaviour. 

--Jani
 [2000-12-07 03:13 UTC] sniper@php.net 
Reclassified as documentation problem.

array_pop($arr) (and array_shift($arr) ?) returns NULL in case the $arr is
an empty array or it isn't an array at all. 


--Jani
 [2001-03-17 00:33 UTC] jmcastagnetto@php.net 
Fixed in manual (CVS)
 
PHP Copyright © 2001-2025 The PHP Group
All rights reserved. 		Last updated: Tue Nov 04 12:00:01 2025 UTC