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Bug #70154 date_parse() not returning false for missing time components
Submitted: 2015-07-27 14:05 UTC Modified: 2015-07-27 16:48 UTC
From: abodera at gmail dot com Assigned:
Status: Verified Package: Date/time related
PHP Version: 5.6.11 OS: Linux
Private report: No CVE-ID: None
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 [2015-07-27 14:05 UTC] abodera at gmail dot com
Description:
------------
date_parse() is expected to return false for missing values.

For example: 

    date_parse('1st Aug')['year'] === false;

As soon as you provide day of week, the hour, minute, second components magically become 0 (as in 00:00:00) even though they do not exist:

    date_parse('Sat 1st Aug')['hour'] === 0; // expected: false
    date_parse('Sat 1st Aug')['minute'] === 0; // expected: false
    date_parse('Sat 1st Aug')['second'] === 0; // expected: false


See: http://3v4l.org/HvND2

Test script:
---------------
<?php

print_r(date_parse('Sat 1st Aug'));


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 [2015-07-27 16:48 UTC] cmb@php.net
-Status: Open +Status: Verified
 [2015-07-27 16:48 UTC] cmb@php.net
I can confirm the different behavior.

It occurs to me that this might be an issue with
TIMELIB_UNHAVE_TIME[1], where h, i, s and f might have to be set
to TIMELIB_UNSET.

[1] <https://github.com/derickr/timelib/blob/2015.01/parse_date.re#L116>
 
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