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Bug #7008 Virtual() does not work with Output Buffering
Submitted: 2000-10-04 03:35 UTC Modified: 2000-11-21 07:31 UTC
From: rich at todobebe dot com Assigned:
Status: Closed Package: Output Control
PHP Version: 4.0.2 OS: RedHat 6.2
Private report: No CVE-ID: None
View Developer Edit
 [2000-10-04 03:35 UTC] rich at todobebe dot com 
I'm using apache 1.3.12.

Configure Line ( from phpinfo() ):
./configure' '--with-gd=/usr/local' '--with-jpeg-dir=/usr/local' '--with-ttf=/usr/local' '--with-apxs=/www/bin/apxs' '--with-mysql=/usr/local/mysql' '--enable-sysvsem' '--enable-sysvshm' '--with-zlib' '--disable-debug' '--enable-inline-optimization' '--enable-wddx' '--enable-sockets' '--with-mm'

The bit of code that does it on my setup:

<?php
ob_start();

virtual( $HTTP_SERVER_VARS['PATH_INFO'] . '?' . $QUERY_STRING );
	
$content = ob_get_contents();

ob_end_clean();
?>

The code in the virtual() call should obviously be replaced with something relevant on your setup.

When virtual is called, the output is immediately sent to the browser and not assigned to $content . I have a virtually identical script using an include() instead of virtual() and it works perfectly.

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 [2000-11-21 07:31 UTC] stas@php.net 
This is because virtual actually calls another Apache
handler which executes another sub-request, outside of the
PHP process. Meaning, you cannot use OB mechanism with
virtual, because when Apache executes virtual(), it know
nothing on OB mechanism - in fact, it knows nothing about
PHP that run it either.

So you better use include() in this case. It's also more
portable.
 
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