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Bug #65240 Return code not updating exit status
Submitted: 2013-07-10 20:14 UTC Modified: 2013-07-11 18:48 UTC
Votes:2
Avg. Score:4.0 ± 0.0
Reproduced:2 of 2 (100.0%)
Same Version:1 (50.0%)
Same OS:2 (100.0%)
From: rkelley at transperfect dot com Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 5.4.17 OS: Linux
Private report: No CVE-ID: None
View Developer Edit
 [2013-07-10 20:14 UTC] rkelley at transperfect dot com 
Description:
------------
When the top level function does a return, that code is not reflected in the exit status.

Test script:
---------------
php -r 'return(1);' ; echo $?



Expected result:
----------------
1

Actual result:
--------------
0

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 [2013-07-11 06:06 UTC] laruence@php.net
-Status: Open +Status: Not a bug
 [2013-07-11 06:06 UTC] laruence@php.net 
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

php -r 'exit(0);' ; echo $?
 [2013-07-11 18:48 UTC] rkelley at transperfect dot com 
I see in the manual where it say return will end the execution if it is in the top level function or a script but it does not state what it does with the return value explicit for a script. When filling this bug I referred to C++ where a return 1 in the main function would result in a exit code of 1 being seen on the shell.
 
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