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[2011-04-12 20:27 UTC] iliaa@php.net
-Status: Open
+Status: Bogus
[2011-04-12 20:27 UTC] iliaa@php.net
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Last updated: Mon Nov 03 20:00:02 2025 UTC |
Description: ------------ I found out that foreach sometimes doesn't run through elements added to an array when the value is passed by reference. I haven't tested enough to say it for sure, but I think it happens only on elements added on what would be the last iteration of foreach. Test script: --------------- $array = array('a', 'b', 'c'); foreach ($array as $i => &$val) { echo $val.' '; if ($i % 2 == 1) $array[] = $val.'2'; } Expected result: ---------------- When it reaches $array[1] (b), it creates $array[3] with the value "b2". Then it runs through $array[3] and creates $array[4] with the value "b22". After that, it should run through $array[4] too, outputting altogether "a b c b2 b22" and stopping. Actual result: -------------- Since at the start of the iteration, $array[3] is the last element of the array, after $array[4] is created in that iteration, it doesn't run through it, outputting just "a b c b2". Still, $array[4] is created.