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Bug #54321 Foreach not running through added elements when passed by reference
Submitted: 2011-03-20 13:45 UTC Modified: 2011-04-12 20:27 UTC
From: unokpasabaxaki at yahoo dot es Assigned:
Status: Not a bug Package: *Programming Data Structures
PHP Version: 5.2.17 OS:
Private report: No CVE-ID: None
 [2011-03-20 13:45 UTC] unokpasabaxaki at yahoo dot es
I found out that foreach sometimes doesn't run through elements added to an array 
when the value is passed by reference. I haven't tested enough to say it for sure, 
but I think it happens only on elements added on what would be the last iteration 
of foreach.

Test script:
$array = array('a', 'b', 'c');
foreach ($array as $i => &$val) {
   echo $val.' ';
   if ($i % 2 == 1) $array[] = $val.'2';

Expected result:
When it reaches $array[1] (b), it creates $array[3] with the value "b2". Then it 
runs through $array[3] and creates $array[4] with the value "b22". After that, it 
should run through $array[4] too, outputting altogether "a b c b2 b22" and 

Actual result:
Since at the start of the iteration, $array[3] is the last element of the array, 
after $array[4] is created in that iteration, it doesn't run through it, 
outputting just "a b c b2". Still, $array[4] is created.


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 [2011-04-12 20:27 UTC]
-Status: Open +Status: Bogus
 [2011-04-12 20:27 UTC]
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at and the instructions on how to report
a bug at

foreach makes a copy of the array to run through, any changes to that array within 
the scope of foreach() construct are not visible to it.
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