Description:
------------
Optional result argument of parse_str now has to be predefined as an
array.  In previous versions the 2nd optional argument of parse-str 
could either be an undefined variable or even an existing non-array 
variable. Either way the function returned the expected array populated with the parsed string. In PHP 6.0 the argument has to 
be a pre-defined array.  

Modifying the test below as follows:

<?php
		
$s1 = "first=val1&second=val2&third=val3";
$res1 = array();
parse_str($s1, $res1);
var_dump($res1);

?>

fixes the problem but this is not required on 5.2 and 5.3 so requirement will break applications when they are ported to PHP6. 

Is this an intended change in behavior or just a side affect 
introduced when parse_str modified to use zend_parse_parameters()?


Should code not be: 

	if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "s|z", &enc_string, &enc_string_len, &result) == FAILURE) {
		return;
	}

to maintain the 5./5.3 behaiviour ?

Reproduce code:
---------------
<?php
		
$s1 = "first=val1&second=val2&third=val3";
parse_str($s1, $res1);
var_dump($res1);

?>

Expected result:
----------------
array(3) {
  [u"first"]=>
  unicode(4) "val1"
  [u"second"]=>
  unicode(4) "val2"
  [u"third"]=>
  unicode(4) "val3"
}

Actual result:
--------------
NULL
Warning: parse_str() expects parameter 2 to be array, null given in ......