PHP :: Bug #48573 :: E-notated strings improperly cast as integers

Bug #48573	E-notated strings improperly cast as integers
Submitted:	2009-06-16 19:08 UTC	Modified:	2009-06-23 20:14 UTC
From:	josh at mykoala dot com	Assigned:
Status:	Open	Package:	Scripting Engine problem
PHP Version:	5.2.9	OS:	Mac OS X 10.5.7
Private report:	No	CVE-ID:

[2009-06-16 19:08 UTC] josh at mykoala dot com

Description:
------------
When an E notated integer is in a string, and you try to cast it to an integer, the value stops at anything non-integer, reducing the ability to cast notated numbers.  It does not first check or convert the value to a float to account for E notation.

The documentation on type juggling doesn't mention this limitation, and it is not the expected result.

Reproduce code:
---------------
$ php -r 'var_dump((int)"5.6401418785e+05");'
int(5)
$ php -r 'var_dump((int)5.6401418785e+05);'
int(564014)
$ php -r 'var_dump((int)(float)"5.6401418785e+05");'
int(564014)

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[2009-06-16 19:54 UTC] josh at mykoala dot com

> When an E notated integer

When an E notated float*

intval() on the string also (predictably) produces the same result as casting to int

[2009-06-23 19:57 UTC] sjoerd-php at linuxonly dot nl

Thank you for your bug report.

A workaround for what you want is adding 0:
php -r 'echo 0 + "5.6401418785e+05";'
564014.18785

[2009-06-23 20:14 UTC] josh at mykoala dot com

Well, round() produces the desired result -- the large number without any decimals.  Adding zero just casts to float, which takes the decimals into consideration, and is the same as:

$ php -r 'var_dump((float)"5.6401418785e+05");'
float(564014.18785)

It's that conversion to int directly that makes Iron Eyes Cody cry.

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