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[2008-05-07 08:25 UTC] derick@php.net
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Last updated: Thu Nov 06 22:00:01 2025 UTC |
Description: ------------ I have prepared for the login data but i am getting bug like Parse error: syntax error, unexpected $end ....Kindly check on this and revert Reproduce code: --------------- <? session_start()?> <html> <head> <title>login </title> </head> <body> <h2>login</h2> <? $links="<a href='main.php'>click to </a><br><br><a href='logout.php'>click</a>"; if($user&&$pass){ if($logged_in_user==$user){ echo $user.",you are already logged in.<br><br>"; echo $links; exit; } $db=mysql_connect("localhost"); mysql_select_db("RAGHU",$db); $result=mysql_query("SELECT * FROM FRUIT WHERE name ='".$user."' AND password= PASSWORD('".$pass."')"); if(!$result){ echo "sorry, there has ben hitch"; exit; } if(mysql_num_rows($result)>0){ $logged_in_user = $user; session_register("logged_in_user"); echo "welcome,".$logged_in_user.".<br><br>"; echo $links; exit; } else { echo "invalid login ,please try again<br><br>"; } ?> <FORM METHOD=POST ACTION="login.php"> Your username: <input name="user" type=text maxlength=20 size=20> <br> your password: <input name="pass" type=password maxlength=10 size=10> <br> <input type=submit value="login"> </body> </html> Expected result: ---------------- Login input and password input with the submit button....