Description:
------------
If you try to use this syntax in a class to declare a class member:

  $foo[1] = 1;

You get a parse error. Prepending a visibility keyword doesn't change 
anything, nor does using a string key instead of a numeric key.

Note: this was seen in v5.2.4. I don't have 5.2.5 to test against. I 
did, however, test it against a couple of 5.0.x versions, where I also 
saw a parse error, so this is definitely a multi-version issue.

Reproduce code:
---------------
File test.php

<?php

class foo {
	$bar[1] = 1;
}

?>


Expected result:
----------------
I'd expect $bar[1] to be created as member of class foo and assigned the 
value of 1. This syntax isn't explicitly covered in the classes section 
of the docs as far as I can see; the only restriction that's given is 
this:

"The default value must be a constant expression, not (for example) a 
variable, a class member or a function call."

Since I'm assigning a constant value, since this array assignment syntax 
is otherwise valid, and since the array() syntax works, I'd expect this 
syntax to work, as well.

Actual result:
--------------
% php -l test.php 

Parse error: syntax error, unexpected T_VARIABLE, expecting T_FUNCTION 
in test.php on line 4
Errors parsing test.php