Description:
------------
When doing count($var) where $var is not an array, the return = 1.

The problem is when you're doing a check in your code:

if (count($var) > 0){
  //do something
}

This will evaluate as true if $var is not an array. This is a problem if you are doing this:

if (count($var) > 0){
    sort($var); // anything that requires $var to be an array
}

If there is anything in that if statement that requires $var to be an array, there will be a fatal error. I know you can also add an is_array check in there, but that is non-obvious and shouldn't be necessary.

Really, if $var is not an array, count($var) should return false or null, or at least a -1

Reproduce code:
---------------
$var = "foo";

if (count($var) > 0){
  sort($var);
} else {
  echo "The value of var is not greater than zero";
}

Expected result:
----------------
The value of var is not greater than zero

Actual result:
--------------
Warning: sort() expects parameter 1 to be array, string given