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Bug #43533 escapeshellarg('') returns null
Submitted: 2007-12-08 02:58 UTC Modified: 2007-12-09 16:37 UTC
Votes:1
Avg. Score:4.0 ± 0.0
Reproduced:0 of 1 (0.0%)
From: josephk at etelos dot com Assigned:
Status: Closed Package: *Directory/Filesystem functions
PHP Version: 5.2.5 OS: Cent OS 5
Private report: No CVE-ID:
 [2007-12-08 02:58 UTC] josephk at etelos dot com
Description:
------------
escapeshellarg() returns null when passed an empty string instead of returning an empty string.  The documentation doesn't say anything about giving a return value of null.

Reproduce code:
---------------
<?php
var_dump(escapeshellarg(''));
?>

Expected result:
----------------
string ''

Actual result:
--------------
null

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History

AllCommentsChangesGit/SVN commitsRelated reports
 [2007-12-08 10:59 UTC] felipe@php.net
In PHP 5.3.0-dev (cli) (built: Dec  7 2007 22:22:09) it shows:
string(2) "''"
 [2007-12-09 04:30 UTC] crrodriguez at suse dot de
5_2 returns NULL (wrong value) , for some reason 5_3 is right.
 [2007-12-09 16:37 UTC] iliaa@php.net
This bug has been fixed in CVS.

Snapshots of the sources are packaged every three hours; this change
will be in the next snapshot. You can grab the snapshot at
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