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Bug #4281 cannot use a referenced argument with defaulting
Submitted: 2000-04-30 03:36 UTC Modified: 2000-07-04 16:05 UTC
From: andy at qabobala dot xapnet dot com Assigned:
Status: Closed Package: Scripting Engine problem
PHP Version: 4.0 Beta 4 OS: Linux 2.2.14
Private report: No CVE-ID: None
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 [2000-04-30 03:36 UTC] andy at qabobala dot xapnet dot com 
You cant use a reference with a default value (an optional function arg) when defining a function-- the parser will choke on this.

function ($somearg, &$object_ref = 0) {
  if($object_ref == 0) {
     ...
   }
  else { ... }
}

Maybe this fails because php needs a predefined NULL - which is a reference to the NULL object.  


later...

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 [2000-07-04 16:05 UTC] stas at cvs dot php dot net 
Yes you cannot use defaults for reference. 
I am not sure this is possible at all in PHP. 
Initializer should eb a constant, while reference parameter should be modifiable.
 [2003-05-21 05:24 UTC] sailormax at inbox dot lv 
I need take argument-reference, but not obligatory. I write:
---------------------
function foo($arg = '')
{
 ...
}
foo(&$zz); // or foo()
---------------------
and have warning: Call-time pass-by-reference has been deprecated...

in documentation wrote:
~~~~~~~~~~~~~~~~~~~~~~~
Whether to enable the ability to force arguments to be passed by reference at function call time. This method is deprecated and is likely to be unsupported in future versions of PHP/Zend.
~~~~~~~~~~~~~~~~~~~~~~

And how I can now realize not obligatory argument-reference?
 
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