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Bug #418 array function misbehaves if first element is a string containing a number
Submitted: 1998-05-29 21:56 UTC Modified: 1998-05-30 03:40 UTC
From: sam at daemoninc dot com Assigned:
Status: Closed Package: Misbehaving function
PHP Version: 3.0 Release Candidate 5 OS: Solaris 2.5.1
Private report: No CVE-ID: None
View Developer Edit
 [1998-05-29 21:56 UTC] sam at daemoninc dot com 
A string containing a number is being treated the same as a number.

Reproduce with:

$a = array("0", "a", "b");
for (reset($a); $v = current($a); next($a)) {
    echo "$v\n";
}

I would expect this to print three lines with three strings:
0
a
b
instead it prints nothing at all.  If the first string is changed from
"0" to "z", it prints three lines as expected.  Looks like the string
"0" is being treated the same as the number 0.

do-conf contains:
./configure --with-gd=no --with-sybase=/tools1/pkgs/sybase --with-config-file-path=/web/cgi-bin/RC_internal/phpdir/lib --enable-debug=no --enable-safe-mode=yes --with-exec-dir=/web/cgi-bin/RC_internal/phpdir/scripts --bindir=/web/cgi-bin/RC_internal/phpdir/bin

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 [1998-05-30 03:40 UTC] zeev 
You're expectations are wrong.  "0" is false, thus your
loop will have no iterations at all, which is exactly
what should happen.
For reliable array traversal code, look at each() (at
the online documentation or at the php3 mailing list
archives).
 
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