Description:
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According to the operator precdence docs, the modulus operator has precedence over the equals operator.  But that is not in fact how it works, as a recent thread on the php general list has shown.

Reproduce code:
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$s= 5;
$d = 2;
$result = ($s % $d=3);
echo "3 incorrectly assigned to \$d:  \$d=$d\n";
echo "result of mod = $result\n";  //$result here is 2: 5 % 3


Expected result:
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This should give an error, instead it assigns 3 to $d and gives a result of 2.

A parallel bug was reported with respect to the ! and the = operators in bug #17180, which resulted in a statement at the end of the operator precedence document which allows for an exception to the rule. Either the operator precedence rules should be respected or a general inquiry should be made into how php handles = and a general statement about it should be appended to the operator precedence docs.

These exceptions to the operator precedence rules are not allowd in Perl.