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Bug #39383 PHP erroneously converts keys to integer
Submitted: 2006-11-04 20:33 UTC Modified: 2006-11-04 22:44 UTC
From: lamotkin at softhome dot net Assigned:
Status: Not a bug Package: Arrays related
PHP Version: 5.2.0 OS: Windows 98
Private report: No CVE-ID: None
View Developer Edit
 [2006-11-04 20:33 UTC] lamotkin at softhome dot net 
Description:
------------
PHP erroneously converts keys to integer if possible,
but my script is type-sensitive with that code.


Reproduce code:
---------------
$Test =
array(	"" => "No set",
	"1" => "Yes",
	"0" => "No");
var_dump($Test);
echo "<p>";
$Test =
array(	"" => "No set",
	1 => "Yes",
	0 => "No");
var_dump($Test);
echo "<p>";


Expected result:
----------------
'var_dump's must NOT be the same


Actual result:
--------------
'var_dump's ARE the same

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 [2006-11-04 20:38 UTC] derick@php.net 
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

.
 [2006-11-04 21:21 UTC] lamotkin at softhome dot net 
Well, you are right, Derick, the doc covered the issue.
But I believe this is a software design error,
because neither

        in_array($some_var, $Test, true)
nor
        in_array($some_var, $Test, false)

produces no correct results.
But if array keys would be of the type specified
on definition, the

        in_array($some_var, $Test, true)

work right.
 [2006-11-04 21:45 UTC] derick@php.net 
Maybe, but we can't just start breaking things for people so we ain't changing this.
 [2006-11-04 22:44 UTC] lamotkin at softhome dot net 
Oops, I realized a nonsense in my logic,
the 'in_array' in examples above search
for the values, not keys, and they probably
will work right.
I corrected my real script (which implies
a bit more complicated code), and the
described is not an issue for me now ...

Sorry, Derick, for wasting your precious
time.
Please delete this "bug"
from the database.
 
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