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Bug #38165 no error to return non-existent index of a non-array variable
Submitted: 2006-07-20 15:58 UTC Modified: 2006-07-21 08:50 UTC
From: aurelien dot riche at ac-lille dot fr Assigned:
Status: Not a bug Package: Arrays related
PHP Version: 5.1.4 OS: linux
Private report: No CVE-ID: None
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 [2006-07-20 15:58 UTC] aurelien dot riche at ac-lille dot fr 
Description:
------------
There's no error reporting for this code below...
'index' is interpreted as 1 and the value returned is the first letter of string 'hello world'
If it's a normal behavior, can you specify this in the documentation ?


Reproduce code:
---------------
$var = 'hello world';

echo $var['index'];

echo '<br/><br/>';

if(isset($var['index']))
  echo 'OK';

Expected result:
----------------
Notice: Undefined offset: 'index'

Actual result:
--------------
h

OK

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 [2006-07-20 16:00 UTC] tony2001@php.net 
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

$var[0] is perfectly valid and 'index' is autoconverted to 0.
 [2006-07-21 07:11 UTC] aurelien dot riche at ac-lille dot fr 
OK thanks.
I suppose I should do this test instead of before:

if(is_array($var['index']))
  echo 'OK';
 [2006-07-21 08:50 UTC] aurelien dot riche at ac-lille dot fr 
Sorry, this test instead of above :

if(is_array($var) && isset($var['index']))
  echo 'OK';
 
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