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Bug #35870 isset() on ternary operator incorrectly evaluates conditions
Submitted: 2006-01-02 05:56 UTC Modified: 2006-01-02 08:20 UTC
From: jevon at jevon dot org Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 5.1.1 OS: Windows XP
Private report: No CVE-ID: None
View Developer Edit
 [2006-01-02 05:56 UTC] jevon at jevon dot org 
Description:
------------
I'm not sure if this has been submitted before, because it's a bit difficult to search for 'isset' on bugs.php.net.

Basically if you have isset() in a ternary operation (?:), PHP currently evaluates all items in the operation, whereas it shouldn't. I guess this is because isset() is a language construct.

Reproduce code:
---------------
<?php
$x = array();
if (isset($x[1]))
	echo $x[1];
else
	echo 0;

echo isset($x[1]) ? 0 : $x[1];
?>

Expected result:
----------------
0
0

Actual result:
--------------
0
PHP Notice: Undefined offset: 1 in test.php on line 8

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 [2006-01-02 08:20 UTC] sniper@php.net 
Please read again how ternary operator works. 
hint1: isset($x[1]) == false
hint2: when condition in ternary operation evaluates to false, the stuff after : is executed..
 
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