Description:
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when opening a file via ftp as an array 

$logfile=fopen('ftp://example.com/filename.ext',"r");

it returns an error:

500 'SIZE filename.ext': command not understood and example.com is running a Solaris default ftp daemon.

Looking at the latest version 5.1-latest, (I'm assuming that it is using ftp_fopen_wrapper.c):

ftp_fopen_wrapper.c,v 1.85.2.2 2005/11/22 03:01:39
line 450:
        /* find out the size of the file (verifying it exists) */
        php_stream_printf(stream TSRMLS_CC, "SIZE %s\r\n", resource->path);

Is there a reason that you are using a non-standard command SIZE for verifying existance of the file?

Reproduce code:
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$file=fopen('ftp://example.com/filename.ext',"r");

Expected result:
----------------
No error message when doing fopen

Actual result:
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Warning: fopen('ftp://example.com/filename.ext') [function.fopen]: failed to open stream: FTP server reports 500 'SIZE filename.ext': command not understood. in /patrh/to/htdocs/filename.php on line 3