|  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login
Bug #33090 mysql_prepare doesn't return an error
Submitted: 2005-05-21 10:37 UTC Modified: 2005-05-21 11:36 UTC
From: Assigned: georg
Status: Closed Package: MySQLi related
PHP Version: 5.0.4 OS: all
Private report: No CVE-ID:
 [2005-05-21 10:37 UTC]
In later versions of libmysqlclient 4.1 and 5.0 the api 
call mysql_stmt_close also clears mysql->net.error* 
This affects that mysql_prepare doesn't return an error 
with current version of libmysql. 

Reproduce code:

$mysql = new mysqli("localhost", "user", "password", "test");

if (!($stmt = $mysql->prepare("this will never work"))) {
    printf("Error: %s\n", $mysql->error);


Expected result:
Error: You have an error in your SQL syntax; check the 
manual that corresponds to your MySQL server version for 
the right syntax to use near 'this will never work' at 
line 1 

Actual result:


Add a Patch

Pull Requests

Add a Pull Request


AllCommentsChangesGit/SVN commitsRelated reports
 [2005-05-21 11:36 UTC]
This bug has been fixed in CVS.

Snapshots of the sources are packaged every three hours; this change
will be in the next snapshot. You can grab the snapshot at
Thank you for the report, and for helping us make PHP better.

PHP Copyright © 2001-2015 The PHP Group
All rights reserved.
Last updated: Wed Dec 02 06:01:39 2015 UTC