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[2000-01-01 11:44 UTC] tobias at dnet dot it
Unset(), when applied to array elements, leaves holes in the array.
Take this code:
$array = array("a");
unset($array[0]);
$array[] = "d";
var_dump($array);
This will produce the following output with PHP 3.0.12 and 3.0.13:
array(2) {
int(1)
string(1) "d"
}
a) It would make more sense if the index would be 0.
b) var_dump() sees the array as containing two elements. Count() works fine, though. PHP 4.x's var_dump() shows correctly array(1).
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Last updated: Tue Oct 28 01:00:01 2025 UTC |
We are sorry, but can not support PHP 3 related problems anymore. Momentum is gathering for PHP 5, and we think supporting PHP 3 will lead to a waste of resources which we want to put into getting PHP 5 ready. Ofcourse PHP 4 will continue to be supported for the forseeable future. for a) unset doesn't renumber, remember that all php arrays are actually hashes b) well, see message above