Description:
------------
When configuring PHP with MySQL with the following config it fails:

./configure --prefix=/project/compiled/PHP \
--exec-prefix=/project/compiled/PHP \
--with-mysql=/project/compiled/MySQL \
--with-zlib=/usr/local

The error message that config displays is:

checking for mysql_close in -lmysqlclient... no
checking for mysql_error in -lmysqlclient... no
configure: error: mysql configure failed. Please check config.log for more information.

From config.log:

ld: fatal: Symbol referencing errors. No output written to conftest
collect2: ld returned 1 exit status
configure: failed program was:
#line 56453 "configure"
#include "confdefs.h"
/* Override any gcc2 internal prototype to avoid an error.  */
/* We use char because int might match the return type of a gcc2
    builtin and then its argument prototype would still apply.  */
char mysql_error();

int main() {
mysql_error()
; return 0; }


However, if I symlink /project/compiled/MySQL to /usr/local/mysql, everything works perfectly.

I don't want that symlink in there.  Is there a way to do so?

Please let me know.


Reproduce code:
---------------
./configure --prefix=/project/compiled/PHP \
--exec-prefix=/project/compiled/PHP \
--with-mysql=/project/compiled/MySQL \
--with-zlib=/usr/local

Expected result:
----------------
Configure to run without errors

Actual result:
--------------
checking for mysql_close in -lmysqlclient... no
checking for mysql_error in -lmysqlclient... no
configure: error: mysql configure failed. Please check config.log for more information.