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Bug #26234 While Loops
Submitted: 2003-11-13 00:34 UTC Modified: 2003-11-13 00:37 UTC
From: spock1985 at homail dot com Assigned:
Status: Not a bug Package: MySQL related
PHP Version: 4.3.4 OS: Win Xp
Private report: No CVE-ID: None
 [2003-11-13 00:34 UTC] spock1985 at homail dot com
When using a while loop such as in the example below:

It skips over the very first entry within the table. 
Say I have 5 rows which have a lvl of 3, when printing out the name of said row, only the last 4 will print out.

Reproduce code:
mysql_connect (localhost, root, '');
mysql_select_db (Arakaron);
$result=mysql_query ("SELECT * FROM magic WHERE lvl='3'");
$row = mysql_fetch_array($result);
while ($row = mysql_fetch_array($result))
print $row['name'];

Expected result:
I expect to see all 5 names of the rows instead of the last 4.

Actual result:
Only shows the very last 4 rows which have a level of 3.


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 [2003-11-13 00:37 UTC]
your code logic is flawed.  you fetch twice before taking 
any action. drop the first '
$row = mysql_fetch_array($result);' an you should be fine.
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