|
php.net | support | documentation | report a bug | advanced search | search howto | statistics | random bug | login |
PatchesPull RequestsHistoryAllCommentsChangesGit/SVN commits
[2002-11-03 08:11 UTC] moriyoshi@php.net
|
|||||||||||||||||||||||||||
Copyright © 2001-2025 The PHP GroupAll rights reserved. |
Last updated: Sat Nov 01 18:00:01 2025 UTC |
I have installed the php 4.2.3 in W2K Server (en) Box, via ISAPI, the <? phpinfo();?> works fine... but when I write the example as folling... # fils: test.html <html> <head> <title>??าปาณ</title> </head> <body> <H1>Please Input your name:</H1> <form method="POST" action="first.php"> <p><b>Your Name is</b><input type="text" name="text1" size="20"> <input type="submit" value="Commit" name="button1"></p> </form> </body> </html> #file:first.php <? if (!($text)) echo "<H1>Your name is".$text1."</H1>"; else echo "please input your name!"; ?> When I key in some words in the text1 field... and commit... but the first.php just return the following... Your name is: It seems the variable value has not been successfully transiitted to the first.php, or the php can not get the variable's value content correctly.. why this happy???