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Bug #16269 array_splice produces an unexpected result
Submitted: 2002-03-25 15:34 UTC Modified: 2002-07-07 21:38 UTC
From: saschahofmann at gmx dot de Assigned:
Status: Not a bug Package: Arrays related
PHP Version: 4.1.2 OS: windows 2000
Private report: No CVE-ID: None
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 [2002-03-25 15:34 UTC] saschahofmann at gmx dot de 
Hi folks,

I'm using PHP 4.1.2 as module with apache 1.3.23

I have this array:

$array1[0] = array("a" => 3, "b" => 3);
$array1[1] = array("a" => 9, "b" => 3);
$array1[2] = array("a" => 11, "b" => 11);
$array1[3] = array("a" => 11, "b" => 11);
$array1[4] = array("a" => 15, "b" => 11);
$array1[5] = array("a" => 2, "b" => 2);

I want to split the array in to arrays with array1 containing all elements where a = b and array2 a <> b

The correct result should be
even: element 0,2,3,5
uneven: element 1,4

I used the following code to split the array:

foreach ($array as $key = $val) {
    if ($val["a"] == $val["b"]) {
        $array2[] = array_splice($array1,$key,1);
    }
}

$array1 should now contain all uneven elements and $array2 all even elements (with a different structur but that doesn't matters here).

But the result is:
$array1 contains element 1,3,4
$array2 contains 4 elements but one is empty! The data of element 3 are missing.

When I run the script with this comparison:
if ($val["a"] != $val["b"])

I got the correct numbers of elements in each array (2 and 4)
but with wrong values.

I think this is a bug. Please inform me if you have investigated the issue and found a explanation (maybe I did something wrong).

best,
Sascha

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 [2002-03-25 15:36 UTC] saschahofmann at gmx dot de 
foreach ($array1 as $key = $val) {
    if ($val["a"] == $val["b"]) {
        $array2[] = array_splice($array1,$key,1);
    }
}

is the correct code. I forgot the '1' in the first variable
 [2002-03-26 08:04 UTC] sander@php.net 
Your foreach-loop is wrong. It should be 
foreach ($array1 as $key => $val) {

Does it work now?
 [2002-03-26 08:33 UTC] saschahofmann at gmx dot de 
No, that wasn't the reason. I only misspelled the foreach-loop 
when I wrote the bug report (forgot the '1').
Sascha
 [2002-03-26 10:51 UTC] sander@php.net 
That 1 is not what I meant, I was talking about => instead of =.
You are using 
foreach ($array1 as $key = $val) {
and it should be
foreach ($array1 as $key => $val) {

Does it work now?
 [2002-03-26 12:53 UTC] saschahofmann at gmx dot de 
Oh oh, I'm very sorry. I should be more accurated when writing a message :-)

Here is the code again (by copy & paste):
<?php
$array1[0] = array("a" => 3, "b" => 3);
$array1[1] = array("a" => 9, "b" => 3);
$array1[2] = array("a" => 11, "b" => 11);
$array1[3] = array("a" => 11, "b" => 11);
$array1[4] = array("a" => 15, "b" => 11);
$array1[5] = array("a" => 2, "b" => 2);

foreach ($array1 as $key => $val) {
    if ($val["a"] == $val["b"]) {
        $array2[] = array_splice($array1,$key,1);
    }
}
echo "array1:<br>";
echo "<pre>";
var_dump($array1);
echo "</pre>";

echo "<br>array2:<br>";
echo "<pre>";
var_dump($array2);
echo "</pre>";
?>

Please, try it out. You'll get a weird result...
 [2002-03-26 13:37 UTC] sander@php.net 
The problem is you're modifying the array while you're walking through it with foreach. That causes the mess. Don't know what to do with this, though.
 [2002-03-26 14:14 UTC] saschahofmann at gmx dot de 
I suspected this as a possible source for the wrong result and already tried it out.

Here is the modified code again:

<?php

$array1[0] = array("a" => 3, "b" => 3);
$array1[1] = array("a" => 9, "b" => 3);
$array1[2] = array("a" => 11, "b" => 11);
$array1[3] = array("a" => 11, "b" => 11);
$array1[4] = array("a" => 15, "b" => 11);
$array1[5] = array("a" => 2, "b" => 2);

$array_backup = $array1;

foreach ($array1 as $key => $val) {
    if ($val["a"] == $val["b"]) {
        $array2[] = array_splice($array_backup,$key,1);
    }
}
echo "array_backup:<br>";
echo "<pre>";
var_dump($array_backup);
echo "</pre>";

echo "<br>array2:<br>";
echo "<pre>";
var_dump($array2);
echo "</pre>";

?>

To be sure I even loaded $array_backup manually to exclude the unlikely case of referencing the variable instead of copying.

In my special case the curious behaviour of the function is not that important. I find another way to solve the problem. But I thought it is a good idea to inform you and your developing team.
I think it is a bug.
 [2002-07-07 21:38 UTC] andrei@php.net 
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

You are modifying the array but using the keys from the original one. Bogus.
 
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