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[2001-08-10 00:28 UTC] cynic@php.net
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Last updated: Thu Oct 30 18:00:02 2025 UTC |
I have made it simple for you: $day1=$date["mday"]; $mon1=$date["mon"]; $year1=$date["year"]; $date=$day1.".".$mon1.".".$year1; $query="insert into data (coll) values ($date)"; ERROR!!!! (try to change the Mysql col. attr. to date) ERROR!!!! ----------------------------------------------------- ok try it in an other way.... $pattern="/(\d{1,2})\.(\d{1,2})\.(\d{2,4})/"; if (preg_match($pattern,$heute,$regs)){ echo $regs[3],"-",$regs[2],"-",$regs[1]; $date=implode("-",$regs); $query="insert into data (coll) values ($date)"; ERROR!!!! (try to change the Mysql col. attr. to date) ERROR!!!! --------------------------------------------------- ok try it in an other way.... $mon1 = substr($str,5,2); $day1 = substr($str,8,2); $year1= substr($str,0,4); $date=$day1.".".$mon1.".".$year1; $query="insert into data (coll) values ($date)"; ERROR!!!! (try to change the Mysql col. attr. to date) ERROR!!!! --------------------------------------------------- Summery: php does not return real strings back and only structures or pointers to structures which make the live of the programmers harder than it is! My solution: please create a blody simple function to convert dates to strings ... somthing like: $string=DateToStr($any_date_format); Eventually I'm very sorry folks I find PHP very nice but PHP cannot give any basic solutions for dates which will force me to use Microsoft ASP Yeh!, it is slow but at least it works