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Bug #12401 "break;" doesn't seem to work propery
Submitted: 2001-07-26 10:10 UTC Modified: 2002-04-13 08:44 UTC
From: alenkei at easy2tel dot com Assigned:
Status: Not a bug Package: OCI8 related
PHP Version: 4.0.6 OS: Linux Server 2.2.14-6.1.1
Private report: No CVE-ID: None
 [2001-07-26 10:10 UTC] alenkei at easy2tel dot com
I'm not sure this is a bug.

Maybe one cannot just "break" out of an "if" or "else" block.

I have a html page that accepts a username and password and then calls the code below.


if ((!$username) || (!$password)) {


$connection = OCILogon($username, $password, $db);
if ($connection == false){
   $msg = OCIError($connection)."<BR>";
else do {
	// Looks like we need the "do..while()" so we can "break;" below!
	$stmt = "select * from \"Person\"";
	$cursor = OCIParse($connection, $stmt);
	if (false == $cursor){
		$msg = OCIError($cursor)."<BR>";

	$result = OCIExecute($cursor);
	if (false == $result) {
		$msg = OCIError($cursor)."<BR>";

	echo "<table border=1>";
	echo "
			<td><b>Person Name</b></td>
			<td><b>Person Information</b></td>

	while (OCIFetchInto ($cursor, $values)){
		$leID = $values[0];
		$pName = $values[1];
		$pInfo = $values[2];

		echo "

	echo "</table>";

} while (false);

<TITLE>Secret Area</TITLE>

		<? echo "$msg"; ?>

	  	<form method="POST" action="");>
		<input type="submit" name="logon" value="Back">


The problem is that if I use a user which doesn't have the
"Person" table in its schema the second "break;" (OCIExecute()) causes the following error:

Warning: OCIStmtExecute: ORA-00942: table or view does not exist in /home/httpd/html/sec_html/logon.php on line 25

Fatal error: Cannot break/continue 1 levels in /home/httpd/html/sec_html/logon.php on line 29

My configure line was:
./configure  --without-mysql --with-oci8 --with-apache=../apache_1.3.20 --enable-track-vars --with-openssl

Best regards,
Andrei Lenkei


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 [2002-04-13 08:44 UTC]
i'm sure you found this out in the meantime

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