PHP :: Bug #12042 :: $ can't be escaped when using ereg function

Bug #12042	$ can't be escaped when using ereg function
Submitted:	2001-07-11 05:46 UTC	Modified:	2001-07-11 05:51 UTC
From:	teocl at globalsources dot com	Assigned:
Status:	Not a bug	Package:	*Regular Expressions
PHP Version:	4.0.6	OS:	LINUX
Private report:	No	CVE-ID:	None

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[2001-07-11 05:46 UTC] teocl at globalsources dot com

Please see the codes below:
<?

$arrfile = '<?include("$DOCUMENT_ROOT/TEMPLATES/TOP-BANNER.HTM");?>';

if(eregi("<\?include\(\"\$DOCUMENT_ROOT/TEMPLATES/TOP-BANNER\.HTM\"\);\?>",$arrfile))
        print "good\n";
else
        print "bad\n";

?>

The result will return "bad" because the eregi can't find the expression in the $arrfile. If I removed the $, it will return "good". I guess "$" can't be escaped inside the eregi function. Please help.

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[2001-07-11 05:51 UTC] zak@php.net

This is known and expected behavior.  Please review the regex docs more carefully - also search the php-general mailing list archives.

The quick fix is to place 3 backslashes in front of the $.

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