PHP :: Bug #10389 :: mysql_query(); returns an invalid result resource

Bug #10389	mysql_query(); returns an invalid result resource
Submitted:	2001-04-18 19:45 UTC	Modified:	2001-05-10 05:51 UTC
From:	pmarks at employees dot org	Assigned:
Status:	Closed	Package:	MySQL related
PHP Version:	4.0.4pl1	OS:	Linux
Private report:	No	CVE-ID:	None

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[2001-04-18 19:45 UTC] pmarks at employees dot org

Here is the code I am using that produces the error:

<?php
    $db = mysql_connect("localhost");
    mysql_select_db("ue", $db);
    $result = mysql_query("SELECT * FROM jobsc");
    $rows = mysql_num_rows($result);
?>

on the last line is where the error is generated.  In
any browser, I see:

Warning: Supplied argument is not a valid MySQL result
resource ...

My setup contains apache 1.3.19 with the static PHP 4.0.4pl1
module compiled in.  My configure lines for PHP are:

./configure --with-apache=/home/apache_1.3.19
--with-mysql=/usr/local/mysql

/usr/local/mysql is the install directory for mysql

That is all the information I believe I have, and I'm
relatively sure that PHP is not crashing, per say.

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[2001-04-18 20:26 UTC] cnewbill@php.net

Your query is not returning any rows, and as such mysql_query returns false.  False of course is not a valid mysql result and thus the "Warning".

If you are 100% certain the query returns results then that would be a problem, otherwise this is not a bug.

Please check this query from the mysql command line and reopen if there really is a problem.

-Chris

[2001-04-18 20:29 UTC] cnewbill@php.net

My bad...it would not return false.  It's been a long long day.

But it would return false if the table jobsc did not exist or the database ue did not exist.

-Chris

[2001-04-19 16:42 UTC] pmarks at employees dot org

I checked what you said with mysqladmin and mysql.  The
database "ue" does exist, as does the table "jobsc."  Thanks
for saying something about the table being empty, as it was.
I fixed this problem (I'd had it before, but i just did this new
script by itself to make sure) and added 1 entry to the table "jobsc."  PHP4 still returns the same warning as before on the
"SELECT * FROM jobsc"  and in the mysql console, executing
that instruction returns the one and only row in the table jobsc.

[2001-04-19 17:40 UTC] cnewbill@php.net

This appears to be related to 4.0.4pl1.  I can reproduce it on a 4.0.4pl1 box, but not anything newer.

Can you try 4.0.5 or a CVS snapshot? http://snaps.php.net/

-Chris

[2001-05-10 05:51 UTC] sniper@php.net

Can't reproduce. If still problem with latest CVS, reopen.

--Jani

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