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Bug #69691 ::class behaviour inside assertion
Submitted: 2015-05-22 09:09 UTC Modified: 2015-05-22 11:57 UTC
Avg. Score:4.0 ± 0.0
Reproduced:2 of 2 (100.0%)
Same Version:1 (50.0%)
Same OS:2 (100.0%)
From: red dot led0 at gmail dot com Assigned:
Status: Not a bug Package: Class/Object related
PHP Version: 5.6.9 OS: Linux
Private report: No CVE-ID: None
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From: red dot led0 at gmail dot com
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 [2015-05-22 09:09 UTC] red dot led0 at gmail dot com
'MyClass::class' construction works different inside and outside of assertion if namespace given.

Test script:

namespace Test; // Without namespace works fine

assert_options(ASSERT_ACTIVE, 1);

class A { }

class B extends A { }

$test1 = $test2 = $name_a = $name_b = null;

$test1 = is_subclass_of(B::class, A::class);

assert('($test2 = is_subclass_of(B::class, A::class)) || 1');

assert('($name_a = A::class) || 1');
assert('($name_b = B::class) || 1');

var_dump($test1, $test2);

var_dump(A::class, $name_a);
var_dump(B::class, $name_b);

Expected result:
string(6) "Test\A"
string(6) "Test\A"
string(6) "Test\B"
string(6) "Test\B"

Actual result:
string(6) "Test\A"
string(1) "A"
string(6) "Test\B"
string(1) "B"


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 [2015-05-22 11:57 UTC]
-Status: Open +Status: Not a bug
 [2015-05-22 11:57 UTC]
String asserts have scoping equivalent to eval(). Among other things, this means that they have their own namespace context - they do not share the namespace or import list of the context they occur in.

If you want to stay in the same context, don't use strings and pass your expression directly. In PHP 7 this will incur no cost if asserts are disabled.
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