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Doc Bug #63058 Change of: "Example #1 mysql_select_db() example"
Submitted: 2012-09-10 23:24 UTC Modified: 2012-09-11 01:53 UTC
From: jangirke at gmail dot com Assigned:
Status: Wont fix Package: Documentation problem
PHP Version: Irrelevant OS: Irrelevant
Private report: No CVE-ID: None
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From: jangirke at gmail dot com
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 [2012-09-10 23:24 UTC] jangirke at gmail dot com
From manual page:
// make foo the current db
$db_selected = mysql_select_db('foo', $link);
if (!$db_selected) {
    die ('Can\'t use foo : ' . mysql_error());
//Tell what is inside $link. Does $link call the function mysql_connect('localhost', 'mysql_user', 'mysql_password') or the return values?
$db_selected = mysql_select_db('DatabaseName', $link);
if (!$db_selected) {
    die ('Unable to connect to database.' . mysql_error());


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 [2012-09-11 01:53 UTC]
I don't see how that would improve the example. In general, manual pages aren't intended to stand completely alone: the fact that mysql_connect() returns a resource is documented on the mysql_connect() page (which is itself linked in the See Also section), and the basics of function calls and PHP syntax are covered earlier in the manual. It's impractical to document those sorts of things on an example-by-example basis.

Marking won't fix.
 [2012-09-11 01:53 UTC]
-Status: Open +Status: Wont fix
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