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Bug #62 s/printf() problem with %% in format string
Submitted: 1998-02-12 01:31 UTC Modified: 1998-02-13 11:54 UTC
From: walton at nordicdms dot com Assigned:
Status: Closed Package: Other
PHP Version: 3.0b4 OS: WinNT
Private report: No CVE-ID: None
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From: walton at nordicdms dot com
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 [1998-02-12 01:31 UTC] walton at nordicdms dot com
%% appears to steal an argument from the s/printf()
argument list.  When %% is the last %-construct in the
format string, the lack of an argument is silently ignored.
In other cases, unpleasant things happen:

printf("%d %%",1);
1 %

printf("%d %% %d",1,2);
Warning:  sprintf: too few arguments

printf("%d %% %d",1,2,3);
1 % 3


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AllCommentsChangesGit/SVN commitsRelated reports
 [1998-02-13 11:54 UTC] zeev
Fixed by Stig
 
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