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Bug #48313 fgetcsv() does not report empty row as documented
Submitted: 2009-05-17 20:16 UTC Modified: 2009-05-18 18:49 UTC
Avg. Score:3.5 ± 0.5
Reproduced:2 of 2 (100.0%)
Same Version:2 (100.0%)
Same OS:2 (100.0%)
From: bitworks at web dot de Assigned:
Status: Closed Package: Filesystem function related
PHP Version: 5.2.9 OS: Windows XP SP3
Private report: No CVE-ID: None
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 [2009-05-17 20:16 UTC] bitworks at web dot de
reading data with fgetcsv() an empty row wil not be returned as one array element pointing to NULL, as it is described in documentation

the result for the record will be

array(1) {
  string(0) ""

instead of

array(1) {

Expected result:
array(1) {

Actual result:
array(1) {
  string(0) ""


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 [2009-05-17 20:34 UTC] bitworks at web dot de
<?php    ### bugreport_48313.php ###

    $fh = fopen('csv02.txt','r');
    if (!$fh) die('wrong filename');
    $_file = array();
    $_rec = array();

    while (false!==($_rec = fgetcsv($fh, 8192, ';','"')))
        $_file[] = $_rec;

    echo "<pre>\r\n";
    echo "</pre>\r\n";


You will need a csv-file with some data and also an empty line in it.

"1";"Erste Zeile";"0";"Text"
"2";"Zeite Zeile";"0.11";"mehr Text"
"3";"Dritte Zeile";"";"kein Eintrag vorhanden"

"5";"nach der Leerzeile";"22";"letzter Eintrag"
 [2009-05-18 18:49 UTC]
This bug has been fixed in CVS.

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