|  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login
Bug #44083 virtual() not outputting results if zlib.output_compression = On
Submitted: 2008-02-09 13:44 UTC Modified: 2010-06-21 00:32 UTC
Avg. Score:5.0 ± 0.0
Reproduced:3 of 3 (100.0%)
Same Version:1 (33.3%)
Same OS:1 (33.3%)
From: mjsabby at gmail dot com Assigned:
Status: Wont fix Package: Apache2 related
PHP Version: 6CVS-2008-02-09 (CVS) OS: Fedora 7
Private report: No CVE-ID: None
View Add Comment Developer Edit
Welcome! If you don't have a Git account, you can't do anything here.
You can add a comment by following this link or if you reported this bug, you can edit this bug over here.
Block user comment
Status: Assign to:
Bug Type:
From: mjsabby at gmail dot com
New email:
PHP Version: OS:


 [2008-02-09 13:44 UTC] mjsabby at gmail dot com
It seems in PHP6 (from CVS), virtual() doesn't work, well not the way it used to if zlib.output_compression = On

In fact, as soon as the virtual request is called, the remaining output's after that call are also not sent to the browser.

However, apache access logs say that they served correct amount of bytes.

Setting zlib.output_compression = Off makes it work just fine.

Reproduce code:
 Hello World 

echo "I can see this\n";
echo "\nBut not this";

Expected result:
I can see this
Hello World
But not this

Actual result:
I can see this


Add a Patch

Pull Requests

Add a Pull Request


AllCommentsChangesGit/SVN commitsRelated reports
 [2009-04-20 20:16 UTC] mv at supportex dot net
reproduced 100% on 1 box with 5.2.6-2.fc9 httpd 2.2.9-1.fc9 i386, so setting zlib_output_compression Off helps

on the other box, virtual() is not working regardless of setting zlib_output_compression Off nor setting buffering Off
 [2010-06-21 00:32 UTC]
-Status: Open +Status: Wont fix
 [2010-06-21 00:32 UTC]
Old trunk related.
PHP Copyright © 2001-2024 The PHP Group
All rights reserved.
Last updated: Sun Apr 21 09:01:29 2024 UTC