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Bug #40669 problem with ternary operateor
Submitted: 2007-02-28 18:36 UTC Modified: 2007-02-28 19:11 UTC
From: milman at gmx dot de Assigned:
Status: Not a bug Package: Scripting Engine problem
PHP Version: 5.2.1 OS:
Private report: No CVE-ID: None
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 [2007-02-28 18:36 UTC] milman at gmx dot de 
Description:
------------
$a = 1 + (1) ? 2 : 5 ;

should be the same as

$a = 1 + ((1) ? 2 : 5);

as 

$a = 3 ;

Reproduce code:
---------------
<?php
echo "<body><xmp>\n" ;

$a = 1 + (1) ? 2 : 5 ;
echo "wrong: $a\n" ;

$a = 1 + ((1) ? 2 : 5);
echo "right: $a\n" ;

echo "</xmp></body>\n" ;
?> 

Expected result:
----------------
wrong: 3
right: 3



Actual result:
--------------
wrong: 2
right: 3

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 [2007-02-28 18:49 UTC] tony2001@php.net 
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

http://www.php.net/manual/en/language.operators.php
 [2007-02-28 19:11 UTC] milman at gmx dot de 
sorry, but i dosn't understand.

why must i write 

$a = 1 + ((1) ? 2 : 5);

and 

$a = 1 + (1) ? 2 : 5 ;
get a wrong result.

that is totaly unexpected.

i think it is to easy to say in documentation you should use
() with ternary operator.

than it should get a syntax-error when using without in expressions.
but not a wrong result.
 
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