php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login
Bug #36500 problem with readfile
Submitted: 2006-02-23 21:10 UTC Modified: 2006-02-23 21:13 UTC
From: neppo at pobox dot sk Assigned:
Status: Not a bug Package: Variables related
PHP Version: 5.1.2 OS: Windowns XP
Private report: No CVE-ID: None
View Add Comment Developer Edit
Welcome! If you don't have a Git account, you can't do anything here.
You can add a comment by following this link or if you reported this bug, you can edit this bug over here.
(description)
Block user comment
Status: Assign to:
Package:
Bug Type:
Summary:
From: neppo at pobox dot sk
New email:
PHP Version: OS:

 

 [2006-02-23 21:10 UTC] neppo at pobox dot sk
Description:
------------
i've got file where is written e.g. 16 and filesize is 2 B
i gave readfile("x.txt") to variable, name is not important, and then when i called variable e.g. echo $read it showed me 162 . it means that it wrote the file and after it is written filesize. so i can't use readfile in variable

Reproduce code:
---------------
$read = readfile("x.txt");
echo $read;

Expected result:
----------------
x.txt = 16
filesize = 2

$read = readfile("x.txt");
echo $read;   /write 16

Actual result:
--------------
x.txt = 16
filesize = 2

$read = readfile("x.txt");
echo $read;   /is writting 162

Patches

Add a Patch

Pull Requests

Add a Pull Request

History

AllCommentsChangesGit/SVN commitsRelated reports
 [2006-02-23 21:13 UTC] tony2001@php.net
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

http://php.net/readfile is not http://php.net/file_get_contents
 
PHP Copyright © 2001-2024 The PHP Group
All rights reserved.
Last updated: Fri Mar 29 00:01:28 2024 UTC