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Bug #35767 *printf argument swapping doesn't work with constants
Submitted: 2005-12-21 21:38 UTC Modified: 2005-12-21 21:40 UTC
From: capiCrimm at gmail dot com Assigned:
Status: Not a bug Package: Class/Object related
PHP Version: 5CVS-2005-12-21 (snap) OS: WinXP/GNU Debian
Private report: No CVE-ID: None
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From: capiCrimm at gmail dot com
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 [2005-12-21 21:38 UTC] capiCrimm at gmail dot com
Using argument swapping with *printf you get a parse error thats the same as if you included a variable in the string. 

Reproduce code:
class Slaughter
  const pig = "%1/$s is dead!";
  public function __construct(){
    printf(self::pig,'Oinker ');
new Slaughter;

Expected result:
Oinker is dead!

Actual result:
Parse error: parse error, unexpected '"' in <> on line <>


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 [2005-12-21 21:40 UTC] capiCrimm at gmail dot com
I hate being stupid, the I was using forward slashes... :\
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