php.net |  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login
Bug #29459 Parser loses output of simple expression ending with an addition.
Submitted: 2004-07-30 18:14 UTC Modified: 2004-08-05 23:09 UTC
From: c dot lohl at web dot de Assigned:
Status: Not a bug Package: *Math Functions
PHP Version: 4.3.7 OS: Win2k Server
Private report: No CVE-ID: None
View Add Comment Developer Edit
Welcome! If you don't have a Git account, you can't do anything here.
You can add a comment by following this link or if you reported this bug, you can edit this bug over here.
(description)
Block user comment
Status: Assign to:
Package:
Bug Type:
Summary:
From: c dot lohl at web dot de
New email:
PHP Version: OS:

 

 [2004-07-30 18:14 UTC] c dot lohl at web dot de
Description:
------------
The parser loses the first part of the output of an expression containig numbers and strings with a simple addition at the end.

Environment: Win2k Server (SP4) with Apache 2.0.50 and PHP 4.3.7 (installed via TSW 3.3.3), no changes in php.ini (but the paths).
Sorry if this information does not fit your needs, I'm totally new to PHP (found this problem reading a tutorial...)

Reproduce code:
---------------
<?
  echo "This doesn't work: <br>";
  $i = 16;
  $j = 26;
  echo $i."+".$j."=".$i+$j;

  echo "<br> No problem with this: <br>";
  $k = 42;
  echo $i."+".$j."=".$k;
?>

Expected result:
----------------
Output: 16+28=42

Actual result:
--------------
Output: 42

Patches

Add a Patch

Pull Requests

Add a Pull Request

History

AllCommentsChangesGit/SVN commitsRelated reports
 [2004-07-30 18:16 UTC] c dot lohl at web dot de
Sorry, forgot this: the problem does not occur with operators  -, *, /.
 [2004-08-05 23:09 UTC] edink@php.net
echo $i."+".$j."=".($i+$j); will work much better.

 
PHP Copyright © 2001-2020 The PHP Group
All rights reserved.
Last updated: Sat Dec 05 12:01:22 2020 UTC