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Bug #2854 mysql_fetch_field won't return object after fetch_row
Submitted: 1999-11-28 21:07 UTC Modified: 1999-11-28 23:01 UTC
From: john-marc at usa dot net Assigned:
Status: Closed Package: MySQL related
PHP Version: 4.0 Beta 2 OS: unix
Private report: No CVE-ID: None
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From: john-marc at usa dot net
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 [1999-11-28 21:07 UTC] john-marc at usa dot net 
<?
echo "<HTML><BODY>";
  $db = mysql_connect("localhost", "root");
  $active_db = mysql_select_db("bus");
  $q_sel = "select * from WHO_SHOP ";
  $BusInfo = mysql_query($q_sel ,$db);
  echo "<table border=1>";
  while ($row = mysql_fetch_row($BusInfo)) {
   $fnum=0;
   while ($fn = mysql_fetch_field($BusInfo)) {
     $fieldname = $fn->name;
     $fval= $row[$fnum];
     echo "<TR><TD>$fieldname</TD><TD>$fval</TD></TR>";
     $fnum += 1;
   }
}
echo "</table></HTML></BODY>";
?>

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 [1999-11-28 23:01 UTC] rasmus at cvs dot php dot net 
Your code doesn't make a lot of sense.  It isn't like the field names are going to change from one row to the next, so there is no point putting the mysql_fetch_field() inside the row loop.
And if all you want is the name, see the mysql_fetch_array() function.  Call it with a second arg of MYSQL_ASSOC
 
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