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Bug #28290 Throwing exception in eval'led code is not handled correctly
Submitted: 2004-05-05 23:47 UTC Modified: 2005-01-22 01:00 UTC
Votes:2
Avg. Score:4.5 ± 0.5
Reproduced:2 of 2 (100.0%)
Same Version:0 (0.0%)
Same OS:0 (0.0%)
From: arnoud at rattink dot com Assigned:
Status: No Feedback Package: Scripting Engine problem
PHP Version: 5.0.0RC2 OS: SuSE Linux 8.2
Private report: No CVE-ID: None
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From: arnoud at rattink dot com
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 [2004-05-05 23:47 UTC] arnoud at rattink dot com 
Description:
------------
The code below prints GRRRRRRRR. This is incorrect as the 
throwing of the exception is supposed to bring us 
immediately to the catchblock. It is also inconsistent, 
since I can replace the eval with just  
$f = AAAAAARRRRRRRRG(); 
and then it skips the echo. 
 

Reproduce code:
---------------
<?
function AAAAAARRRRRRG(){
    throw new Exception("AAAAAARRRRRRG");
}

try {
    eval('$f = AAAAAARRRRRRG();');
    echo "GRRRRRRRR\n";
}
catch(Exception $e) {
    echo "Exception caught nice and clean\n";
}
?>

Expected result:
----------------
I do not expect to see GRRRRRRRR. 

Actual result:
--------------
GRRRRRRRR 
Exception caught nice and clean

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 [2004-05-11 05:07 UTC] vkatragadda at email dot com 
hello, i dont think this is a bug. i believe the line after eval gets executed by default. i think everything in the try{} block is supposed to get executed, and then the catch{} block is called...
 [2004-05-11 05:10 UTC] vkatragadda at email dot com 
hello, i dont think this is a bug. i believe the line after eval gets executed by default. i think everything in the try{} block is supposed to get executed, and then the catch{} block is called...
 [2004-05-14 00:01 UTC] arnoud at rattink dot com 
That is not true. Example: 
 
<? 
function f() { throw new Exception("I am an exception"); 
} 
 
try 
{ 
    $v = f(); 
    echo "This is not supposed to get printed\n"; 
} 
catch(Exception $e) { 
    echo "caught exception\n"; 
} 
?> 
 
This just prints 'caught exception'. That is entirely 
correct. Now if you were right, then the above code should 
execute both echos. It does not, so is that a bug? I say 
it's a catch 22. 
 
Either this program, or the one with the 'eval' works out 
wrong. Personally I believe the whole idea of 'throwing an 
exception' is that you bypass all intermediate code and 
land straight into the 'catch' block. At least, that's how 
it works in C++ and Java.
 [2005-01-15 00:23 UTC] tony2001@php.net 
Please try using this CVS snapshot:

  http://snaps.php.net/php5-STABLE-latest.tar.gz
 
For Windows:
 
  http://snaps.php.net/win32/php5.0-win32-latest.zip

Can't reproduce, seems to be fixed.
 [2005-01-22 01:00 UTC] php-bugs at lists dot php dot net 
No feedback was provided for this bug for over a week, so it is
being suspended automatically. If you are able to provide the
information that was originally requested, please do so and change
the status of the bug back to "Open".
 [2009-10-08 12:41 UTC] cedric at conseil-creation dot com 
Don't think it's a bug... just read the following not in PHP.NET eval manual:

"If there is a parse error in the evaluated code, eval() returns FALSE and execution of the following code continues normally."

What about this code (?!):
---------------------------
    if ( eval('$f = AAAAAARRRRRRG();') )
    {
        echo "GRRRRRRRR\n";
    }
---------------------------

Or this one:
---------------------------
    if ( !eval('$f = AAAAAARRRRRRG();') )
    {
    // parse error
    }
    echo "GRRRRRRRR\n";
    }
---------------------------
 
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