Description:
------------
There appears to be a problem with php that doesn't allow arrays to be passed by value.  The fix appears to be something similar to: http://bugs.php.net/bug.php?id=6417
if (PZVAL_IS_REF(*p))
{
   SEPARATE_ZVAL(p);
} else {
   zval_add_ref(p);
}

It would appear that that logic is missing in one place or another.  I could not track it down myself.  Code similar to this appears to be copy/pasted in various places.

Reproduce code:
---------------
$array = array(1);

// This line makes the call to theFunction() act as if passed by ref.?
$reference =& $array[0];

echo $array[0], '<br>';
theFunction($array);

echo $array[0], '<br>';

function theFunction($array) {
    $array[0] = 2;
}

Expected result:
----------------
you should get 1 and 1

Actual result:
--------------
instead you get 1 and 2!