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Bug #22775 Fatal error from require() exits with status=0
Submitted: 2003-03-18 20:50 UTC Modified: 2003-03-19 02:23 UTC
From: gk at proliberty dot com Assigned:
Status: Closed Package: CGI/CLI related
PHP Version: 4.3.2RC1 OS: linux RH 7.2; kernel 2.4.18
Private report: No CVE-ID: None
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 [2003-03-18 20:50 UTC] gk at proliberty dot com
According to the manual, require() differs from include() in that failure to open a file is FATAL in require().

Yet, using sapi/cgi/php or sapi/cli/php, fatal errors from require() exit with status=0 instead of non-zero, as one would expect from a 'fatal' error.

I do not know if this problem is true for ALL fatal errors or not.

Calling exit(1) works correctly however, which provides an awkward, but useful, workaround to this problem:
if (!$success) exit(1);

Here is my test file: /htdocs/common/test/junk/test.php

//the following fixes the problem:
//if (!$success) exit(1);

[root@p3 sapi]# cli/php -f /htdocs/common/test/junk/test.php; echo status="$?";

Warning: main(non_existent_file) []: failed to open stream: No such file or directory in /usr/local/apache/htdocs/common/test/junk/test.php on line 4

Fatal error: main() []: Failed opening required 'non_existent_file' (include_path='.:/usr/local/apache/htdocs/common/php:/usr/local/lib/php') in /usr/local/apache/htdocs/common/test/junk/test.php on line 4
[root@p3 sapi]# cli/php -r 'exit(1);'; echo status="$?";
[root@p3 sapi]#


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 [2003-03-18 21:46 UTC] gk at proliberty dot com
Actually I was mistaken about the workaround:
THERE IS NO WAY TO EXIT CORRECTLY, USING require(); only with include()! Which is contrary to the entire purpose of using require() instead of include().

This does NOT work:
if (!$success) exit(1);

This DOES work:
if (!$success) exit(1);
 [2003-03-19 01:40 UTC] gk at proliberty dot com
improved the title
 [2003-03-19 02:23 UTC]
This bug has been fixed in CVS.

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Last updated: Mon Mar 20 22:03:51 2023 UTC