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Bug #17997 Warning when switch & reference are combined
Submitted: 2002-06-26 11:25 UTC Modified: 2003-10-07 20:51 UTC
Votes:2
Avg. Score:3.0 ± 2.0
Reproduced:1 of 2 (50.0%)
Same Version:1 (100.0%)
Same OS:1 (100.0%)
From: Xuefer at 21cn dot com Assigned:
Status: Closed Package: Scripting Engine problem
PHP Version: 4CVS, 5CVS OS: All
Private report: No CVE-ID: None
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From: Xuefer at 21cn dot com
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 [2002-06-26 11:25 UTC] Xuefer at 21cn dot com 
let the sample code say the problem
<?
error_reporting(E_ALL);

$str1 = '.........$...';
$str = &$str1;
$l = strlen($str);
for ($i = 0; $i < $l; $i ++)
{
	switch ($str{$i})
	{
	case '$':
		$str = '123'; // change string
		$i = -1; // set to -1, for next loop to be 0
		$l = strlen($str); // u know what this do
		break;

	default:
		echo $str{$i};
	}
}
?>

-----------
result:
-----------
.........
Notice: Uninitialized string offset: 9 in d:\myfile\wwwroot\our-sky.com\test.php on line 19
123


how ever, if i change
	$str = '123';
to:
	$s = '123';
	$str = &$s;

no wanning

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AllCommentsChangesGit/SVN commitsRelated reports
 [2002-07-23 16:45 UTC] hholzgra@php.net 
the error message is on the closing '}' of the switch ...
does switch re-evaluate its argument on termination?
this is scary!
 [2003-08-10 18:12 UTC] helly@php.net 
Yes it refetches the variable passed to switch() to check whether it must be freed or not.
 [2003-10-07 12:01 UTC] zeev@php.net 
This bug has been fixed in CVS.

In case this was a PHP problem, snapshots of the sources are packaged
every three hours; this change will be in the next snapshot. You can
grab the snapshot at http://snaps.php.net/.
 
In case this was a documentation problem, the fix will show up soon at
http://www.php.net/manual/.

In case this was a PHP.net website problem, the change will show
up on the PHP.net site and on the mirror sites in short time.
 
Thank you for the report, and for helping us make PHP better.

Fixed
 [2003-10-07 20:51 UTC] sniper@php.net 
Fixed in PHP 5, won't fix in PHP 4.
 
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