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Bug #17116 Bitwise & does not give expected results for positive numbers
Submitted: 2002-05-09 08:17 UTC Modified: 2002-07-01 17:39 UTC
From: lindsay dot marshall at ncl dot ac dot uk Assigned:
Status: Closed Package: Math related
PHP Version: 4.2.0 OS: redhat 7.2
Private report: No CVE-ID: None
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 [2002-05-09 08:17 UTC] lindsay dot marshall at ncl dot ac dot uk 
I have a piece of code that effectively does this :

$r->f = 8191;
$c->m = 7;

$r->f & $c->m returns 0!!

The above code works fine when tested standalone, but the equivalent code in my program generates 0. I can write ;

echo $r->status.' '.$current->mask.' '.($r->status&$current->mask);

and the output I get is

8191 7 0

If I write :

$a1=7;$a2=8191;
echo $r->status.' '.$current->mask.' '.($a1&$a2);

I get

8191 7 7

Something is getting confused somewhere!!

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 [2002-05-09 08:27 UTC] lindsay dot marshall at ncl dot ac dot uk 
I just tried the following:

$a1 = $r->status;
$a2 = $current->mask;
echo $a1.' '.$a2.' '.($a1&$a2);

And it still prints out 8191 7 0

I feel as though I am doing something really stupid here,  but cannot for the life of me see what it is.
 [2002-05-09 08:32 UTC] lindsay dot marshall at ncl dot ac dot uk 
Oh, and before you say "BOGUS - see 7755"

1) I am not using negative integers
2) I think that 7755 is a serious bug and needs to be fixed properly as someone else commented.
3) It is clearly intermittent or at least depends on past history in some way.
 [2002-05-09 09:08 UTC] rasmus@php.net 
1) You sure you aren't &'ing strings together?  
2) 7755 has been fixed - try it
3) Doubt that
 [2002-07-01 15:41 UTC] derick@php.net 
Please reopen this report if this problem is still not fixed for you.

Derick
 [2002-07-01 17:39 UTC] sniper@php.net 
Just close it..
 
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