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Bug #14915 for statement returns nothing.
Submitted: 2002-01-07 15:00 UTC Modified: 2002-01-07 15:26 UTC
From: jacob at keystreams dot com Assigned:
Status: Not a bug Package: Unknown/Other Function
PHP Version: 4.1.0 OS: Linux 2.4.9
Private report: No CVE-ID: None
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From: jacob at keystreams dot com
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 [2002-01-07 15:00 UTC] jacob at keystreams dot com 
when issuing the following syntactically incorrect 'for' statement nothing was returned (note the semi-colon before the parenthesis) even though at least one loop should take place. Should not a parse error be returned?

for ($i = $start; $i <= 10; $i++); {
echo 'something';
}

 './configure' '--with-mysql' '--with-apache=../apache_1.3.22' '--enable-track-vars' '--with-curl' '--with-dom' '--with-zlib'

This is a public/production server so debugging is turned off.

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 [2002-01-07 15:26 UTC] torben@php.net 
No bug; the code you have here is perfectly valid,
although it contains one of those irritatingly hard-to-catch
typo bugs. The semicolon indicates an empty statement. Your 
code says essentially "For every value of $i from $start up 
to and including 10, do nothing--then echo 'something'".

For instance, the following are equivalent:

  for ($i = 1; $i <= 10; $i++) {}

...and...

  for ($i = 1; $i <= 10; $i++);


Cheers,

Torben
 
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