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Bug #1452 $i = $i++ fails
Submitted: 1999-05-25 18:19 UTC Modified: 1999-05-25 18:31 UTC
From: jmorrow at alum dot mit dot edu Assigned:
Status: Closed Package: Misbehaving function
PHP Version: 3.0.7 OS: RedHat Linux 5.2
Private report: No CVE-ID: None
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From: jmorrow at alum dot mit dot edu
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 [1999-05-25 18:19 UTC] jmorrow at alum dot mit dot edu 
The following doesn't work:

$i = 0;
while($i < 50) {
	print $i."\n";
	$i = $i++;
}

$i remains stuck on zero.  The identical construct in C:

int i;
i = 0;
while(i < 50) {
  printf("%d\n",i);
  i = i++;
}

has the expected behavior (it prints 0 to 49).  I know that this is a very obscure case, but I still think it's a bug.

My config line:

./configure  --with-apache=../apache_1.3.3 --with-gd=/usr/local --with-mysql=/usr/local/mysql --with-ldap=/usr/local --enable-debug=no --enable-track-vars=yes

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 [1999-05-25 18:31 UTC] zeev at cvs dot php dot net 
In fact, if that loop hangs for you, than it succeeds doing what
it's supposed to do.  $i=$i++ is equivalent to an empty statement.
Consult the documentation regarding what post-increment is to
understand why.

You could do what you want by choosing any of the following:
$i = ++$i; or
$i++; or
++$i;

The last one being the quickest of them all.
 
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