|  support |  documentation |  report a bug |  advanced search |  search howto |  statistics |  random bug |  login
Bug #10529 for() error
Submitted: 2001-04-27 15:06 UTC Modified: 2001-04-29 06:03 UTC
From: mottalli at sinectis dot com dot ar Assigned:
Status: Closed Package: Unknown/Other Function
PHP Version: 4.0.4pl1 OS: Windows / Linux
Private report: No CVE-ID: None
View Add Comment Developer Edit
Anyone can comment on a bug. Have a simpler test case? Does it work for you on a different platform? Let us know!
Just going to say 'Me too!'? Don't clutter the database with that please !
Your email address:
Solve the problem:
38 - 32 = ?
Subscribe to this entry?

 [2001-04-27 15:06 UTC] mottalli at sinectis dot com dot ar
Trying to make a script that showed the letters from A to Z using the following code:

   for ($i = 'A'; $i <= 'Z'; $i++) {
      echo "$i<br>";      

I saw that the script outputted the first letters (A-Z) but then it started to display AA, AB, AC [...] YZ.
Replacing the 'Z' above to 'Y' (or any other letter between B and Y) makes the script show correctly the letters from A to that letter. 
Replacing letters to lowercase and/or single quotation marks to double causes the same error.

This happened both in PHP 4.0.4pl1 under Windows and in PHP 4.0.1pl1 under Linux.


Add a Patch

Pull Requests

Add a Pull Request


AllCommentsChangesGit/SVN commitsRelated reports
 [2001-04-27 15:23 UTC]
I'm not even sure that is supposed to work like that.  Guys?

Why don't you use this instead?

for ($i = ord('A'); $i <= ord('Z'); $i++) {
     echo chr($i)."<br>";

 [2001-04-27 16:05 UTC] mottalli at sinectis dot com dot ar
I agree the code was a bit strange, but I found it weird that it worked with any letter but Z.

The suggested code worked. Thanks!

 [2001-04-29 06:03 UTC]
This happens because PHP works on strings and the increment of "Z" as a string is "AA". "AA" is smaller than "Z".

PHP Copyright © 2001-2021 The PHP Group
All rights reserved.
Last updated: Thu May 06 07:01:25 2021 UTC