Description:
------------
I found and unexpected behavior in the syntax checking. When you write a ';' after the open brace, the parser doesn't display an error or notice message, and executes the code with the last element of the array. I test this in php5.3 and php5.2.

This "innocent" ; is realy hard to debug.

The enviroments:

joac@pepino ~/ReposGcoop $ php -v
PHP 5.3.3 with Suhosin-Patch (cli) (built: Jul 25 2010 12:50:19) 
Copyright (c) 1997-2009 The PHP Group
Zend Engine v2.3.0, Copyright (c) 1998-2010 Zend Technologies

debdev@jaula:~/www$ php -v
PHP 5.2.6-1+lenny9 with Suhosin-Patch 0.9.6.2 (cli) (built: Aug  4 2010 03:25:57) 
Copyright (c) 1997-2008 The PHP Group
Zend Engine v2.2.0, Copyright (c) 1998-2008 Zend Technologies
    with Xdebug v2.0.3, Copyright (c) 2002-2007, by Derick Rethans


Test script:
---------------
<?php
function show_array(&$data_array){
    foreach ($data_array as $key=>$value);
    {   
        print "$key => $value\n";
        if ( is_array( $value ) ){
           show_array1( $value );
           print "End of nested Array\n";
        }   
    }   
};
$evil_array = array (
        'item1' => array ( 'item1_1' => array( 'item1_1_1' => 1, 'item1_1_2' => 2 ),
        'item1_2' => array( 'item1_2_1' => 3,),
        ),  
    'item2' => '4'); 

show_array($evil_array);
?>
Output:

joac@pepino ~/ReposGcoop $ php bugphp.php 
item2 => 4


Expected result:
----------------
I expect some error or notice for this syntax error.

Actual result:
--------------
joac@pepino ~/ReposGcoop $ php bugphp.php 
item2 => 4