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Bug #21782 array key comparision issue(?)
Submitted: 2003-01-20 15:44 UTC Modified: 2003-01-20 19:13 UTC
From: carlos at wfmh dot org dot pl Assigned:
Status: Not a bug Package: Arrays related
PHP Version: 4.2.3 OS: Linux GNU/Debian
Private report: No CVE-ID: None
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 [2003-01-20 15:44 UTC] carlos at wfmh dot org dot pl 
test.php:
<?php
  $val1 = "any";
  $test = array("any"=>"any", "3"=>"+3", "2"=>"+2",
                "1"=>"+1", "0"=>"0", "-1"=>"-1",
                "-2"=>"-2", "-3"=>"-3" );
  foreach( $test AS $key=>$val )
     printf("'%s' vs. '%s' result: %d\n", $val1, $key, ($key == $val1) );
?>

$ php test.php
'any' vs. 'any' result: 1
'any' vs. '3' result: 0
'any' vs. '2' result: 0
'any' vs. '1' result: 0
'any' vs. '0' result: 1
'any' vs. '-1' result: 0
'any' vs. '-2' result: 0
'any' vs. '-3' result: 0

$ php -v
4.2.3

Shouldn't "'any' vs. '0'" give 0 as result?

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 [2003-01-20 19:13 UTC] iliaa@php.net 
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

0 == 0 hence $key == $val1 is true. Not a bug.
 [2003-01-21 02:32 UTC] carlos at wfmh dot org dot pl 
However I expected this behaviour to be numeric index related, I still consider it a bug. Mostly becasue I compared "any" (which ain't "0") with "0", and the result should be false, as these two are not equal. It does not matter that "any" is the 1st element in the array (hence the 'internal' index 0 is used). I gave an "any" index to this element, so I can't quite understand why it's ok to that PHP evaluates different condition than programmer wrote.
 
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