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Last updated: Thu Oct 30 04:00:02 2025 UTC |
in my php code i have: echo "<B>Numero de Base de Datos</B> : ".mysql_list_dbs($sql)."<BR>"; # ERROR echo "<B>Numero de Tablas en ifrprueba</B> : ".mysql_list_tables("ifrprueba",$sql)."<BR>"; #ERROR ifrprueba is a database that exists. The result of these funcions are: Numero de Base de Datos : 5 Numero de Tablas en ifrprueba : 6 The point is that there are not 5 Databases, but 3. And there are not 6 tables in that database but 1. bbs:/usr/local/bin # ./mysqlshow -u ifr -p Enter password: +-----------+ | Databases | +-----------+ | ifrprueba | | mysql | | test | +-----------+ bbs:/usr/local/bin # ./mysqlshow -u ifr -p ifrprueba Enter password: Database: ifrprueba +--------+ | Tables | +--------+ | test | +--------+ Thank You. Josafat Moragrega